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NCARB ARE 5.0 Project Development and Documentation Exam Sample Questions (Q83-Q88):

NEW QUESTION # 83
Where is the proper place to put a vapor barrier in a cold climate?

A. In the cavity of the framing space
B. On the exterior between the framing and the sheathing
C. On the interior between the gypsum wallboard and the framing
D. On the exterior between the metal siding and the sheathing

Answer: C

Explanation:
In cold climates, the vapor drive is from the warm interior to the cold exterior during winter. The vapor retarder/barrier belongs on the warm-in-winter side of the assembly-i.e., behind the interior gypsum, before the framing/insulation-to prevent interior moisture from reaching cold layers where it could condense.
PDD references: Psychrometrics & vapor drive; vapor retarder placement (ASHRAE; IBC/IECC guidance; ARE 5.0 PDD-Thermal & Moisture Protection).

NEW QUESTION # 84
An architect needs to reduce the budget by $150,000 for a proposed civic auditorium. Currently the project requires the following flooring materials:
* Stained concrete: 100,000 square feet
* Carpet: 50,000 square feet
* Ceramic tile: 20,000 square feet
* Vinyl composite tile (VCT): 25,000 square feet
The flooring material costs are as follows:
* Stained concrete: $6.00/sq ft
* Sealed concrete: $2.00/sq ft
* Carpet: $8.75/sq ft
* Ceramic tile: $15.00/sq ft
* VCT: $5.75/sq ft
* Vinyl plank flooring: $7.00/sq ft
Which of the following combinations of changes results in these savings?

A. Change 20,000 sq ft of stained concrete to VCT and substitute 30,000 sq ft of vinyl plank flooring for carpet.
B. Change 15,000 sq ft of VCT to vinyl plank flooring and substitute 10,000 sq ft of VCT for carpet.
C. Change 25,000 sq ft of stained concrete to sealed concrete and substitute 30,000 sq ft of vinyl plank flooring for carpet.
D. Change 20,000 sq ft of stained concrete to VCT and substitute 10,000 sq ft of VCT for ceramic tile.

Answer: D

Explanation:
Verified answer: C. Change 20,000 sq ft of stained concrete to VCT and substitute 10,000 sq ft of VCT for ceramic tile.
Comprehensive Detailed Explanation with all NCARB ARE 5.0 Project Development and Documentation (PDD) Study Guide References:
Calculate savings for each option by comparing current costs to proposed changes.
Verified answer: C. Change 20,000 sq ft of stained concrete to VCT and substitute 10,000 sq ft of VCT for ceramic tile.
Comprehensive Detailed Explanation with all NCARB ARE 5.0 Project Development and Documentation (PDD) Study Guide References:
Calculate savings for each option by comparing current costs to proposed changes.

Check if this matches required savings:
No, it's less than $150,000. So let's check others briefly.
Total savings = $100,000 + $52,500 = $152,500 # Meets and exceeds required savings

Options A and B will be less, so the answer should be D.
Summary:
Option D results in approximately $152,500 savings, meeting the $150,000 target.
Reference:
NCARB ARE 5.0 Review Manual, Project Cost Control and Materials chapter Construction cost estimating principles and value engineering strategies Change 20,000 sf stained concrete ($6.00/sf) to VCT ($5.75/sf) Savings per sf = $6.00 - $5.75 = $0.25 Total savings = 20,000 sf × $0.25 = $5,000 Substitute 10,000 sf of VCT ($5.75/sf) for ceramic tile ($15.00/sf) Savings per sf = $15.00 - $5.75 = $9.25 Total savings = 10,000 sf × $9.25 = $92,500 Total savings = $5,000 + $92,500 = $97,500 Check if this matches required savings:
No, it's less than $150,000. So let's check others briefly.
Option D:
Change 25,000 sf stained concrete ($6.00/sf) to sealed concrete ($2.00/sf) Savings per sf = $6.00 - $2.00 = $4.00 Total = 25,000 × 4.00 = $100,000 Substitute 30,000 sf vinyl plank ($7.00/sf) for carpet ($8.75/sf) Savings per sf = $8.75 - $7.00 = $1.75 Total = 30,000 × 1.75 = $52,500 Total savings = $100,000 + $52,500 = $152,500 # Meets and exceeds required savings Options A and B will be less, so the answer should be D.
Summary:
Option D results in approximately $152,500 savings, meeting the $150,000 target.
Reference:
NCARB ARE 5.0 Review Manual, Project Cost Control and Materials chapter Construction cost estimating principles and value engineering strategies

NEW QUESTION # 85
For which of the following reasons is sheet piling used? (Check the three that apply)

A. A pile cap needs support.
B. A grade beam needs support.
C. The excavation adjoins a property line and the adjacent property cannot be disturbed.
D. An excessive slope on the sides of the excavation would be required.
E. Raked shoring should be created.
F. The soil surrounding an excavation site will not support itself during or after the digging.

Answer: C,D,F

Explanation:
Sheet piling is a type of earth retention system used in excavations to prevent soil collapse. Reasons include:
D). When the natural soil slope is too steep to remain stable, sheet piling acts as a vertical barrier.
E). When soil cannot support itself during excavation, sheet piles provide lateral support.
F). When excavation is adjacent to a property line or existing structure and adjacent soil must not be disturbed.
Options A (grade beam support), B (raked shoring), and C (pile cap support) are not typical or primary uses of sheet piling.
Reference:
NCARB ARE 5.0 Review Manual, Site Design and Construction chapter
Geotechnical engineering and excavation support best practices

NEW QUESTION # 86
Temporary shoring of a masonry wall should remain in place until what point?

A. Lateral bracing connections are complete
B. Mortar joints are struck
C. Foundations are backfilled
D. Horizontal reinforcing is installed

Answer: A

Explanation:
(PDD) Study Guide References:
Temporary shoring in masonry construction supports walls until they gain sufficient stability. It should remain in place until:
The wall is laterally braced or tied back to a stable structure to resist wind and other lateral loads.
Mortar may have hardened but shoring removal depends on the overall stability.
Horizontal reinforcing and backfilling provide some support but do not replace lateral bracing.
Thus, temporary shoring should remain until all lateral bracing connections are complete, ensuring the wall's stability.
Reference:
NCARB ARE 5.0 Review Manual, Construction Methods chapter
Masonry construction standards and OSHA guidelines on temporary shoring

NEW QUESTION # 87

Refer to the exhibit.
The exterior cast-in-place concrete wall of a heated building is insulated with polyurethane slabs.
The concrete will be warmest in the winter if the insulation is applied as shown in which of the following?

A. C
B. A
C. B
D. D

Answer: D

Explanation:
To keep the concrete warmest in winter, place the continuous insulation on the exterior so the concrete mass stays inside the thermal envelope and sees interior temperatures. This reduces heat loss, limits risk of interstitial condensation at the concrete surface, and improves thermal lag. Option D shows all polyurethane insulation on the outside of the wall; A and B place some or all insulation inside, and C splits it-both allow more winter heat loss from the concrete.
PDD references: Building envelope heat flow & thermal mass strategy; continuous insulation placement (ASHRAE Fundamentals; NCARB ARE 5.0 PDD-Envelope & Thermal/Moisture Protection, CSI Div 07).

NEW QUESTION # 88
......

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